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100x^2-300=x
We move all terms to the left:
100x^2-300-(x)=0
We add all the numbers together, and all the variables
100x^2-1x-300=0
a = 100; b = -1; c = -300;
Δ = b2-4ac
Δ = -12-4·100·(-300)
Δ = 120001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{120001}=\sqrt{49*2449}=\sqrt{49}*\sqrt{2449}=7\sqrt{2449}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7\sqrt{2449}}{2*100}=\frac{1-7\sqrt{2449}}{200} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7\sqrt{2449}}{2*100}=\frac{1+7\sqrt{2449}}{200} $
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